What is the phase difference between the flux | vedclass

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(C) The magnetic flux $\phi$ linked with a coil rotating in a magnetic field $B$ is given by $\phi = BA \cos(\omega t)$.According to Faraday's law of

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$\frac{\pi}{2}$

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(C) The magnetic flux $\phi$ linked with a coil rotating in a magnetic field $B$ is given by $\phi = BA \cos(\omega t)$.According to Faraday's law of electromagnetic induction,the induced emf $e$ is given by $e = -\frac{d\phi}{dt}$.Substituting the expression for $\phi$: $e = -\frac{d}{dt} (BA \cos(\omega t)) = BA\omega \sin(\omega t)$.Using the trigonometric identity $\sin(	heta) = \cos(	heta - \frac{\pi}{2})$,we can write $e = BA\omega \cos(\omega t - \frac{\pi}{2})$.Comparing the phase of the flux $(\omega t)$ and the phase of the induced emf $(\omega t - \frac{\pi}{2})$,the phase difference is $\frac{\pi}{2}$.

What is the phase difference between the flux linked with a coil rotating in a magnetic field and the induced emf produced in it?

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