What is the value of effective magnetic momen | vedclass

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Question

(B) The electronic configuration of $Cr$ $(Z=24)$ is $[Ar] 3d^5 4s^1$. In the $+3$ oxidation state, $Cr^{3+}$ loses three electrons to form $[Ar] 3d^3

Vedclass · Accepted Answer

$3.87$

Vedclass · Answer

(B) The electronic configuration of $Cr$ $(Z=24)$ is $[Ar] 3d^5 4s^1$. In the $+3$ oxidation state, $Cr^{3+}$ loses three electrons to form $[Ar] 3d^3$. This configuration contains $n = 3$ unpaired electrons. The effective magnetic moment $\mu$ is calculated using the formula $\mu = \sqrt{n(n+2)} \ BM$. Substituting $n=3$, we get $\mu = \sqrt{3(3+2)} = \sqrt{15} \approx 3.87 \ BM$.

What is the value of effective magnetic moment found in $+3$ oxidation state of Chromium $(Z=24)$ (in $BM$)?

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