What should be subtracted from p(x) = x^{2} + | vedclass

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(C) Let the polynomial be $p(x) = x^{2} + 9x + 20$. According to the Remainder Theorem,if $p(x)$ is divided by $(x + 2)$,the remainder is $p(-2)$. Sub

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(C) Let the polynomial be $p(x) = x^{2} + 9x + 20$. According to the Remainder Theorem,if $p(x)$ is divided by $(x + 2)$,the remainder is $p(-2)$. Substitute $x = -2$ into the polynomial: $p(-2) = (-2)^{2} + 9(-2) + 20$ $p(-2) = 4 - 18 + 20$ $p(-2) = 6$. For the polynomial to be divisible by $(x + 2)$,the remainder must be $0$. Therefore,we must subtract the remainder $6$ from the polynomial $p(x)$ so that the new polynomial becomes divisible by $(x + 2)$.

What should be subtracted from $p(x) = x^{2} + 9x + 20$ so that the resulting polynomial is divisible by $x + 2$?

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