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(D) For a set of vectors to result in a null vector,they must form a closed polygon when placed head-to-tail.If $n = 2$,the vectors must have equal ma

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$2$

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(D) For a set of vectors to result in a null vector,they must form a closed polygon when placed head-to-tail.If $n = 2$,the vectors must have equal magnitudes and opposite directions to sum to zero. Since the problem states the vectors have different magnitudes,$n = 2$ is impossible.If $n = 3$,the vectors can form a triangle,which is a closed polygon,provided the sum of the lengths of any two sides is greater than the third side.For any $n \ge 3$,it is possible to form a closed polygon with vectors of different magnitudes.Therefore,the value of $n$ cannot be $2$.

When $n$ vectors of different magnitudes are added,we get a null vector. Then the value of $n$ cannot be

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