When vec A cdot vec B = - |A||B|,then | vedclass

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(C) The dot product of two vectors is defined as $\vec A \cdot \vec B = |A||B| \cos 	heta$,where $	heta$ is the angle between the vectors.Given that

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$\vec A$ and $\vec B$ act in the opposite direction

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(C) The dot product of two vectors is defined as $\vec A \cdot \vec B = |A||B| \cos 	heta$,where $	heta$ is the angle between the vectors.Given that $\vec A \cdot \vec B = - |A||B|$,we can equate the two expressions:$|A||B| \cos 	heta = - |A||B|$Dividing both sides by $|A||B|$ (assuming non-zero vectors),we get:$\cos 	heta = - 1$This implies that $	heta = 180^\circ$.Therefore,the vectors $\vec A$ and $\vec B$ act in the opposite direction.

Column $I$	Column $II$
$(A)$ Component along $x$-axis	$(p)$ $5 \text{ unit}$
$(B)$ Component along vector $(2 \hat{i} + \hat{j} + 2 \hat{k})$	$(q)$ $4 \text{ unit}$
$(C)$ Component along $(6 \hat{i} + 8 \hat{j} - 10 \hat{k})$	$(r)$ $0$
$(D)$ Component along $(-3 \hat{i} - 4 \hat{j} + 5 \hat{k})$	$(s)$ None

When $\vec A \cdot \vec B = - |A||B|$,then

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