When vec A cdot vec B = - |A||B|,then | vedclass

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(C) The dot product of two vectors is defined as $\vec A \cdot \vec B = |A||B| \cos 	heta$,where $	heta$ is the angle between the vectors.Given that

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$\vec A$ and $\vec B$ act in the opposite direction

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(C) The dot product of two vectors is defined as $\vec A \cdot \vec B = |A||B| \cos 	heta$,where $	heta$ is the angle between the vectors.Given that $\vec A \cdot \vec B = - |A||B|$,we can equate the two expressions:$|A||B| \cos 	heta = - |A||B|$Dividing both sides by $|A||B|$ (assuming non-zero vectors),we get:$\cos 	heta = - 1$This implies that $	heta = 180^\circ$.Therefore,the vectors $\vec A$ and $\vec B$ act in the opposite direction.

When $\vec A \cdot \vec B = - |A||B|$,then

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