When a ball is thrown up vertically with velocity $u,$ it attains a maximum height $H.$ What should be the velocity so that maximum height becomes $2H$?

$A$ stone is dropped from a certain height and reaches the ground in $5\, s$. If the stone is stopped after $3\, s$ of its fall and then allowed to fall again,then the time taken by the stone to reach the ground for the remaining distance is........$s$.

$A$ ball is thrown vertically upwards with a velocity $u$. What is the distance covered by it in the last $t$ seconds of its upward motion?

$A$ body falling from a high minaret travels $40 \ m$ in the last $2 \ s$ of its fall to the ground. The height of the minaret in meters is (take $g = 10 \ m/s^2$):

Two bodies are held separated by $9.8\,m$ vertically one above the other. They are released simultaneously to fall freely under gravity. After $2\,s$,the relative distance between them is $............\,m$

If a ball is thrown at a velocity of $45 \,m/s$ in the vertical upward direction,what would be the velocity profile as a function of height? (Assume $g = 10 \,m/s^2$)