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(A) According to Brewster's Law, when light is incident at the polarizing angle $(i_p)$, the reflected light is totally plane-polarized.At this angle,

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$30$

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(A) According to Brewster's Law, when light is incident at the polarizing angle $(i_p)$, the reflected light is totally plane-polarized.At this angle, the reflected ray and the refracted ray are perpendicular to each other.Brewster's Law states that $	an(i_p) = \mu$.Given $\mu = \sqrt{3}$, we have $	an(i_p) = \sqrt{3}$, which implies $i_p = 60^{\circ}$.According to Snell's Law, $\mu_1 \sin(i_p) = \mu_2 \sin(r)$, where $r$ is the angle of refraction.Here, $\mu_1 = 1$ (air) and $\mu_2 = \sqrt{3}$.$1 \cdot \sin(60^{\circ}) = \sqrt{3} \cdot \sin(r)$.$\frac{\sqrt{3}}{2} = \sqrt{3} \cdot \sin(r)$.$\sin(r) = \frac{1}{2}$.Therefore, $r = 30^{\circ}$.

When unpolarised light from air is incident on the surface of a medium of refractive index $\sqrt{3}$, the reflected light is totally polarised. The angle of refraction is (in $^{\circ}$)

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