Which among the following complexes is associ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The energy of absorbed light is inversely proportional to the wavelength $(E = \frac{hc}{\lambda})$.Therefore,the complex that absorbs light of ma

Vedclass · Accepted Answer

$[Cu(H_2O)_4]^{2+}$

Vedclass · Answer

(C) The energy of absorbed light is inversely proportional to the wavelength $(E = \frac{hc}{\lambda})$.Therefore,the complex that absorbs light of maximum wavelength must have the minimum crystal field splitting energy $(\Delta_o)$.According to the spectrochemical series,the strength of ligands is $Cl^- Stronger ligands cause larger splitting $(\Delta_o)$.Comparing the complexes:$1$. $[Co(CN)_6]^{3-}$ has strong $CN^-$ ligands,leading to high $\Delta_o$.$2$. $[Co(NH_3)_6]^{3+}$ has $NH_3$ ligands,leading to moderate $\Delta_o$.$3$. $[CoCl(NH_3)_5]^{2+}$ has a weak $Cl^-$ ligand,which reduces the overall $\Delta_o$ compared to $[Co(NH_3)_6]^{3+}$.$4$. $[Cu(H_2O)_4]^{2+}$ involves a $3d^9$ system with $H_2O$ ligands,which generally exhibits a smaller $\Delta_o$ value compared to the $Co^{3+}$ complexes mentioned.Among the given options,$[Cu(H_2O)_4]^{2+}$ has the smallest crystal field splitting energy,corresponding to the maximum wavelength of absorbed light.

Which among the following complexes is associated with the maximum wavelength of light absorbed?

Similar Questions

If $\Delta_{0} < P$,then what is the electronic arrangement of the metal atom/ion in a complex with $d^4$ configuration?

Which among the following is a correct order of increasing field strength of ligands?

Identify the correct decreasing order of wavelength of light absorbed for the following complex ions:
$I. [Co(H_2O)_6]^{3+}$
$II. [Co(CN)_6]^{3-}$
$III. [CoI_6]^{3-}$
$IV. [Co(en)_3]^{3+}$

The electronic configuration of the central metal atom/ion in $\left[ Co(CN)_6 \right]^{3-}$ is

Identify the correct trend given below.
(Atomic No. $= Ti : 22, Cr : 24$ and $Mo : 42$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module