Which of the following contains the maximum n | vedclass

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(A) The number of molecules in a substance is calculated by the formula: $	ext{Number of molecules} = \frac{	ext{Given mass}}{	ext{Molar mass}} 	i

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$1\, g$ of $H_2$

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(A) The number of molecules in a substance is calculated by the formula: $	ext{Number of molecules} = \frac{	ext{Given mass}}{	ext{Molar mass}} 	imes N_A$,where $N_A$ is Avogadro's number $(6.022 	imes 10^{23})$.Since the given mass is $1\, g$ for all options,the number of molecules is inversely proportional to the molar mass.$1$. Molar mass of $H_2 = 2 	imes 1 = 2\, g/mol$. Number of molecules $\propto 1/2 = 0.5$.$2$. Molar mass of $CO_2 = 12 + (2 	imes 16) = 44\, g/mol$. Number of molecules $\propto 1/44 \approx 0.0227$.$3$. Molar mass of $N_2 = 2 	imes 14 = 28\, g/mol$. Number of molecules $\propto 1/28 \approx 0.0357$.$4$. Molar mass of $CH_4 = 12 + (4 	imes 1) = 16\, g/mol$. Number of molecules $\propto 1/16 = 0.0625$.Comparing the values,$H_2$ has the smallest molar mass,therefore it contains the maximum number of molecules.

Which of the following contains the maximum number of molecules?

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One mole of $H_{2}O$ means:
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