Which of the following has the lowest freezing point?

  • A
    $0.1 \ M$ aqueous solution of glucose
  • B
    $0.1 \ M$ aqueous solution of $NaCl$
  • C
    $0.1 \ M$ aqueous solution of $ZnSO_4$
  • D
    $0.1 \ M$ aqueous solution of urea

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In equimolar solutions of glucose,$NaCl$,and $BaCl_2$,the order of osmotic pressure is as follows:

$A$ $0.001 \ molal$ solution of $[Pt(NH_3)_4Cl_4]$ in water has a freezing point depression of $0.0054 \ ^oC$. If $K_f$ for water is $1.80 \ K \ kg \ mol^{-1}$,the correct formulation for the above complex is:

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The measured osmotic pressure of a solution prepared by dissolving $17.4 \ mg$ of $K_2SO_4$ in $2 \ L$ of water at $27^{\circ} C$ is $3.735 \times 10^{-3} \ bar$. The van't Hoff factor is $(R = 0.083 \ L \ bar \ K^{-1} \ mol^{-1}$; atomic weights $K = 39, S = 32, O = 16)$.

The elevation of boiling point of $0.10 \ m$ aqueous $CrCl_{3} \cdot xNH_{3}$ solution is two times that of $0.05 \ m$ aqueous $CaCl_{2}$ solution. The value of $x$ is.........
[Assume $100 \%$ ionisation of the complex and $CaCl_{2},$ coordination number of $Cr$ as $6,$ and that all $NH_{3}$ molecules are present inside the coordination sphere $]$

Which of the following solutions will have the highest boiling point?

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