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(A) The reaction of isobutylene $(CH_3)_2C=CH_2$ with hydrogen bromide $(HBr)$ follows Markovnikov's rule. According to this rule,the negative part of

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$tert-$butyl bromide

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(A) The reaction of isobutylene $(CH_3)_2C=CH_2$ with hydrogen bromide $(HBr)$ follows Markovnikov's rule. According to this rule,the negative part of the addendum $(Br^-)$ attaches to the carbon atom having a lesser number of hydrogen atoms. The reaction proceeds via the formation of a more stable $3^{\circ}$ carbocation intermediate. $(CH_3)_2C=CH_2 + HBr \rightarrow (CH_3)_3C-Br$ The major product formed is $tert-$butyl bromide.

Which of the following is the major product obtained in the reaction of isobutylene with hydrogen bromide?

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