(A) In $\beta-D$-Glucopyranose,the $-OH$ group at the anomeric carbon $(C-1)$ is on the same side as the $-CH_2OH$ group at $C-5$. This means the $-OH

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(A) In $\beta-D$-Glucopyranose,the $-OH$ group at the anomeric carbon $(C-1)$ is on the same side as the $-CH_2OH$ group at $C-5$. This means the $-OH$ group at $C-1$ is in the upward position (equatorial). Option $A$ represents this configuration correctly.