Which of the following statements is correct?

Which will give $Fe^{3+}$ ions in solution?

Match the following Column-$I$ (Reaction) with Column-$II$ (colour of the product or nature):

Column-$I$ (Reaction)	Column-$II$ (colour of the product or nature)
$(A)$ $FeCl_3(aq) + NH_3(aq) \rightarrow$	$(I)$ Green ppt
$(B)$ $AgCl(aq) + NH_3(aq) \rightarrow$	$(II)$ Deep blue
	$(III)$ Brown ppt
	$(IV)$ Colourless solution

The correct answer for the sequence $(A, B)$ is:

$A$ mixture $X$ containing $0.02 \ mol$ of $[Co(NH_3)_5SO_4]Br$ and $0.02 \ mol$ of $[Co(NH_3)_5Br]SO_4$ was prepared in $2 \ L$ of solution.
$1 \ L$ of mixture $X +$ excess $AgNO_3 \to Y$.
$1 \ L$ of mixture $X +$ excess $BaCl_2 \to Z$.
The number of moles of $Y$ and $Z$ are:

The correct option$(s)$ regarding the complex $[Co(en)(NH_3)_3(H_2O)]^{3+}$ $(en = H_2NCH_2CH_2NH_2)$ is (are):
$A$. It has two geometrical isomers
$B$. It will have three geometrical isomers if bidentate 'en' is replaced by two cyanide ligands
$C$. It is paramagnetic
$D$. It absorbs light at longer wavelength as compared to $[Co(en)(NH_3)_4]^{3+}$

Which of the following has a yellow colour?