While computing the mean of grouped data,we assume that the frequencies are
- Aevenly distributed over all the classes
- Bcentred at the lower limits of the classes
- Ccentred at the upper limits of the classes
- Dcentred at the classmarks of the classes
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Similar Questions
For a given frequency distribution,$\bar{x} = 19.7$,$A = 20$,and $n = 50$. Then,$\Sigma f_{i} d_{i} = \ldots$
Easy
View SolutionIn the formula $\bar{x} = a + \frac{\sum f_{i} d_{i}}{\sum f_{i}}$ for finding the mean of grouped data,$d_{i}$ are deviations from $a$ of:
Easy
View SolutionFor a given frequency distribution,$n=100, A=20$ and $\bar{x}=20$. Then,$\Sigma f_{i} d_{i}=\ldots \ldots \ldots . .$
Medium
View SolutionCalculate the mean of the following frequency distribution:
Class $80-90$ $90-100$ $100-110$ $110-120$ $120-130$ $130-140$ $140-150$ $150-160$ $160-170$ Frequency $6$ $18$ $78$ $80$ $100$ $72$ $0$ $40$ $6$
(in $.55$)
| Class | $80-90$ | $90-100$ | $100-110$ | $110-120$ | $120-130$ | $130-140$ | $140-150$ | $150-160$ | $160-170$ |
|---|---|---|---|---|---|---|---|---|---|
| Frequency | $6$ | $18$ | $78$ | $80$ | $100$ | $72$ | $0$ | $40$ | $6$ |
Medium
View SolutionIn the formula $\bar{x} = \frac{\Sigma f_{i} x_{i}}{\Sigma f_{i}}$,$x_{i}$ represents ..........
Easy
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