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(B) rational number $\frac{p}{q}$ has a terminating decimal expansion if the prime factorization of the denominator $q$ is of the form $2^{m} \cdot 5^

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Non-terminating repeating decimal expansion

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(B) rational number $\frac{p}{q}$ has a terminating decimal expansion if the prime factorization of the denominator $q$ is of the form $2^{m} \cdot 5^{n}$,where $m$ and $n$ are non-negative integers.In the given rational number $\frac{129}{2^{2} \cdot 5^{7} \cdot 7^{5}}$,the denominator is $q = 2^{2} \cdot 5^{7} \cdot 7^{5}$.Since the prime factorization of the denominator contains a factor other than $2$ or $5$ (which is $7^{5}$),the decimal expansion is non-terminating repeating.

Without actually performing the long division,state whether the following rational number will have a terminating decimal expansion or a non-terminating repeating decimal expansion: $\frac{129}{2^{2} \cdot 5^{7} \cdot 7^{5}}$

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