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(A) We look for a function whose derivative is $\cos 2x$.Recall that the derivative of $\sin 2x$ is given by:$\frac{d}{dx} (\sin 2x) = 2 \cos 2x$Divid

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$\frac{1}{2} \sin 2x$

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(A) We look for a function whose derivative is $\cos 2x$.Recall that the derivative of $\sin 2x$ is given by:$\frac{d}{dx} (\sin 2x) = 2 \cos 2x$Dividing both sides by $2$,we get:$\frac{1}{2} \frac{d}{dx} (\sin 2x) = \cos 2x$Using the linearity property of the derivative,we can write:$\frac{d}{dx} \left( \frac{1}{2} \sin 2x \right) = \cos 2x$Therefore,an anti-derivative of $\cos 2x$ is $\frac{1}{2} \sin 2x$.

Find an anti-derivative for the following function using the method of inspection:
$\cos 2x$

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Find an anti-derivative for the following function using the method of inspection:$\cos 2x$