(D) The potential energy $U$ of a spring is given by the formula $U = \frac{1}{2} K x^2$,where $K$ is the spring constant and $x$ is the extension or

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If the $Assertion$ is incorrect but $Reason$ is correct.

(D) The potential energy $U$ of a spring is given by the formula $U = \frac{1}{2} K x^2$,where $K$ is the spring constant and $x$ is the extension or compression.This equation shows that $U \propto x^2$.The graph of $U$ versus $x$ represents a parabola,not a straight line.Therefore,the $Assertion$ is incorrect because the relationship is quadratic,not linear.The $Reason$ is correct because it correctly states that the potential energy is proportional to the square of the extension or compression $(U \propto x^2)$.

Class 11 Physics Work, Energy, Power and Collision Work Done by Spring and Potential Energy of Spring

Easy

$Assertion$ : Graph between potential energy of a spring versus the extension or compression of the spring is a straight line.
$Reason$ : Potential energy of a stretched or compressed spring is proportional to the square of extension or compression.

AIIMS 2017 All AIIMS

A
If both $Assertion$ and $Reason$ are correct and the $Reason$ is a correct explanation of the $Assertion$.
B
If both $Assertion$ and $Reason$ are correct but $Reason$ is not a correct explanation of the $Assertion$.
C
If both the $Assertion$ and $Reason$ are incorrect.
D
If the $Assertion$ is incorrect but $Reason$ is correct.

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Class 11

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Work, Energy, Power and Collision

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Work Done by Spring and Potential Energy of Spring

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$A$ spring of force constant $K$ is first stretched by distance $a$ from its natural length and then further by distance $b$. The work done in stretching the part $b$ is .............

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$K$ is the force constant of a spring. The work done in increasing its extension from $l_1$ to $l_2$ will be

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$A$ block of mass $M$ moving on a frictionless horizontal surface collides with a spring of spring constant $K$, as shown in the figure. If the spring compresses by a length $L$, then the maximum momentum of the block is:

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$A$ light elastic spring is placed on a massless platform as shown in the figure. $A$ sand particle of mass $0.1 \ kg$ is dropped onto the spring platform from a height of $0.24 \ m$. The particle sticks to the platform,causing the spring to compress by $0.01 \ m$. From what height should the particle be dropped so that the spring is compressed by $0.04 \ m$ (in $m$)?

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$A$ light spring of length $10 \ cm$ is stretched by $2 \ cm$ when a mass of $20 \ g$ is attached to its end. The mass is pulled until the total length of the spring becomes $14 \ cm$. What is the elastic potential energy stored in the spring (in Joules)?

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$Assertion$ : Graph between potential energy of a spring versus the extension or compression of the spring is a straight line.$Reason$ : Potential energy of a stretched or compressed spring is proportional to the square of extension or compression.

Similar Questions

$A$ spring of force constant $K$ is first stretched by distance $a$ from its natural length and then further by distance $b$. The work done in stretching the part $b$ is .............

$K$ is the force constant of a spring. The work done in increasing its extension from $l_1$ to $l_2$ will be

$A$ block of mass $M$ moving on a frictionless horizontal surface collides with a spring of spring constant $K$, as shown in the figure. If the spring compresses by a length $L$, then the maximum momentum of the block is:

$A$ light spring of length $10 \ cm$ is stretched by $2 \ cm$ when a mass of $20 \ g$ is attached to its end. The mass is pulled until the total length of the spring becomes $14 \ cm$. What is the elastic potential energy stored in the spring (in Joules)?

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$Assertion$ : Graph between potential energy of a spring versus the extension or compression of the spring is a straight line.
$Reason$ : Potential energy of a stretched or compressed spring is proportional to the square of extension or compression.