Based on Crystal Field Theory,show the energy level splitting and determine the $d$-electron configuration and magnetic moment for the central metal atom/ion in the following complexes: $[CoF_6]^{3-}$,$[Co(H_2O)_6]^{2+}$,$[Co(CN)_6]^{3-}$.
(N/A) $1$. $[CoF_6]^{3-}$: $Co^{3+}$ is $3d^6$. $F^-$ is a weak field ligand. Splitting: $t_{2g}^4 e_g^2$. Number of unpaired electrons $(n)$ = $4$. Magnetic moment $\mu = \sqrt{n(n+2)} = \sqrt{4(6)} = \sqrt{24} \approx 4.90 \ BM$.
$2$. $[Co(H_2O)_6]^{2+}$: $Co^{2+}$ is $3d^7$. $H_2O$ is a weak field ligand. Splitting: $t_{2g}^5 e_g^2$. Number of unpaired electrons $(n)$ = $3$. Magnetic moment $\mu = \sqrt{3(5)} = \sqrt{15} \approx 3.87 \ BM$.
$3$. $[Co(CN)_6]^{3-}$: $Co^{3+}$ is $3d^6$. $CN^-$ is a strong field ligand. Splitting: $t_{2g}^6 e_g^0$. Number of unpaired electrons $(n)$ = $0$. Magnetic moment $\mu = 0 \ BM$ (Diamagnetic).
$2$. $[Co(H_2O)_6]^{2+}$: $Co^{2+}$ is $3d^7$. $H_2O$ is a weak field ligand. Splitting: $t_{2g}^5 e_g^2$. Number of unpaired electrons $(n)$ = $3$. Magnetic moment $\mu = \sqrt{3(5)} = \sqrt{15} \approx 3.87 \ BM$.
$3$. $[Co(CN)_6]^{3-}$: $Co^{3+}$ is $3d^6$. $CN^-$ is a strong field ligand. Splitting: $t_{2g}^6 e_g^0$. Number of unpaired electrons $(n)$ = $0$. Magnetic moment $\mu = 0 \ BM$ (Diamagnetic).
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Similar Questions
The magnitude of crystal field stabilisation energy in octahedral field depends on :
$I.$ The nature of the ligand
$II.$ The charge on the metal ion
$III.$ Whether the metal is in the first,second or third row of the transition elements
$I.$ The nature of the ligand
$II.$ The charge on the metal ion
$III.$ Whether the metal is in the first,second or third row of the transition elements
Easy
View SolutionConsider the following complexes:
$[CoCl(NH_3)_5]^{2+},$ $[Co(CN)_6]^{3-}$
$(A)$ $(B)$
$[Co(NH_3)_5(H_2O)]^{3+},$ $[Cu(H_2O)_4]^{2+}$
$(C)$ $(D)$
The correct order of $A, B, C,$ and $D$ in terms of the wavenumber of light absorbed is:
$[CoCl(NH_3)_5]^{2+},$ $[Co(CN)_6]^{3-}$
$(A)$ $(B)$
$[Co(NH_3)_5(H_2O)]^{3+},$ $[Cu(H_2O)_4]^{2+}$
$(C)$ $(D)$
The correct order of $A, B, C,$ and $D$ in terms of the wavenumber of light absorbed is:
The electron distribution in $d^{n}$ coordination complexes depends on the magnitude of crystal field splitting,$(\Delta_{0})$ and pairing energy $(P).$ The condition which favours the formation of high spin complexes is
Crystal field stabilization energy $(CFSE)$ for the complex $[Co(CN)_6]^{3-}$ will be:
Medium
View SolutionFor which of the following complexes will the value of $\Delta_0$ be the lowest?
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