$\left( \frac{1}{1 - 2i} + \frac{3}{1 + i} \right) \left( \frac{3 + 4i}{2 - 4i} \right) = $

  • A
    $\frac{1}{2} + \frac{9}{2}i$
  • B
    $\frac{1}{2} - \frac{9}{2}i$
  • C
    $\frac{1}{4} - \frac{9}{4}i$
  • D
    $\frac{1}{4} + \frac{9}{4}i$

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