A fair die is tossed twice in succession. If | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let $p$ be the probability of getting a six in a single toss,so $p = \frac{1}{6}$.Let $q$ be the probability of not getting a six,so $q = 1 - \fra

Vedclass · Accepted Answer

$X = x_i$$0$$1$$2$$P_i$$\frac{25}{36}$$\frac{5}{18}$$\frac{1}{36}$

Vedclass · Answer

(A) Let $p$ be the probability of getting a six in a single toss,so $p = \frac{1}{6}$.Let $q$ be the probability of not getting a six,so $q = 1 - \frac{1}{6} = \frac{5}{6}$.$X$ denotes the number of sixes in two tosses. $X$ can take values $0, 1, 2$.$P(X = 0) = P(	ext{no six}) = q 	imes q = \frac{5}{6} 	imes \frac{5}{6} = \frac{25}{36}$.$P(X = 1) = P(	ext{one six}) = pq + qp = \frac{1}{6} 	imes \frac{5}{6} + \frac{5}{6} 	imes \frac{1}{6} = \frac{5}{36} + \frac{5}{36} = \frac{10}{36} = \frac{5}{18}$.$P(X = 2) = P(	ext{two sixes}) = p 	imes p = \frac{1}{6} 	imes \frac{1}{6} = \frac{1}{36}$.Thus,the probability distribution is:$X = x_i$$0$$1$$2$$P(x_i)$$\frac{25}{36}$$\frac{5}{18}$$\frac{1}{36}$

$X = x_i$	$0$	$1$	$2$	$3$	$4$	$5$	$6$
$P_i$	$\frac{1}{6}$	$\frac{1}{12}$	$\frac{1}{12}$	$\frac{1}{6}$	$\frac{1}{6}$	$\frac{1}{6}$	$\frac{1}{6}$

$X=x$	$-3$	$0$	$1$	$\alpha$
$P(X=x)$	$\frac{1}{4}$	$K$	$\frac{1}{4}$	$\frac{1}{3}$

$X$	$0$	$1$	$2$	$3$	$4$	$5$	$6$
$P(X)$	$k$	$3k$	$5k$	$7k$	$9k$	$11k$	$13k$

$A$ fair die is tossed twice in succession. If $X$ denotes the number of sixes in two tosses,then the probability distribution of $X$ is given by

Similar Questions

Let the mean and standard deviation of the probability distribution given by the table below be $\mu$ and $\sigma$ respectively. If $\sigma - \mu = 2$,then find the value of $\sigma$.
$X=x$ $-3$ $0$ $1$ $\alpha$
$P(X=x)$ $\frac{1}{4}$ $K$ $\frac{1}{4}$ $\frac{1}{3}$

The probability function of a random variable $X$ is given by $P(X=k)=c k^2$,where $c$ is a constant and $k \in\{0,1,2,3,4\}$. If $\sigma^2$ is the variance of $X$ and $\mu$ is the mean of $X$,then $\sigma^2+\mu^2=$

India plays two matches each against Australia and West Indies. The probabilities of India scoring $0, 1,$ and $2$ points in a match are $0.45, 0.05,$ and $0.50$ respectively. Assuming the results are independent,what is the probability that India scores at least $7$ points?

$A$ random variable $X$ has the following probability distribution:
$X$ $0$ $1$ $2$ $3$ $4$ $5$ $6$
$P(X)$ $k$ $3k$ $5k$ $7k$ $9k$ $11k$ $13k$

Then find $P(X \ge 2)$.

Two bad eggs are mixed accidentally with $10$ good ones. If three eggs are drawn at random from this lot in succession without replacement, then the variance of the probability distribution of the number of bad eggs drawn is

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$X = x_i$	$0$	$1$	$2$
$P_i$	$\frac{25}{36}$	$\frac{5}{18}$	$\frac{1}{36}$