$\left( \frac{a - b}{a} \right) + \frac{1}{2} \left( \frac{a - b}{a} \right)^2 + \frac{1}{3} \left( \frac{a - b}{a} \right)^3 + \dots = $

  • A
    $\log_e(a - b)$
  • B
    $\log_e \left( \frac{a}{b} \right)$
  • C
    $\log_e \left( \frac{b}{a} \right)$
  • D
    $e^{\left( \frac{a - b}{a} \right)}$

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Similar Questions

यदि $|a| < 1$ और $b = \sum_{k=1}^{\infty} \frac{a^k}{k}$ है,तो $a$ का मान क्या होगा?

यदि $1+\frac{\sqrt{3}-\sqrt{2}}{2 \sqrt{3}}+\frac{5-2 \sqrt{6}}{18}+\frac{9 \sqrt{3}-11 \sqrt{2}}{36 \sqrt{3}}+\frac{49-20 \sqrt{6}}{180}+\ldots$ अनंत तक $= 2\left(\sqrt{\frac{b}{a}}+1\right) \log _e\left(\frac{a}{b}\right)$,जहाँ $a$ और $b$ पूर्णांक हैं और $\operatorname{gcd}(a, b)=1$,तो $11 a+18 b$ का मान ............... है।

$\frac{1}{2} + \frac{3}{2} \cdot \frac{1}{4} + \frac{5}{3} \cdot \frac{1}{8} + \frac{7}{4} \cdot \frac{1}{16} + \dots \infty = $

मान ज्ञात कीजिए: $\log_e \sqrt{\frac{1+x}{1-x}}$

$\frac{1}{3} + \frac{1}{2 \cdot 3^2} + \frac{1}{3 \cdot 3^3} + \frac{1}{4 \cdot 3^4} + \dots \infty = $

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