(A) For a prism,the angle of the prism is given by $A = r_1 + r_2$. Since the ray emerges normally from the second face,the angle of emergence $e = 0$

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(A) For a prism,the angle of the prism is given by $A = r_1 + r_2$. Since the ray emerges normally from the second face,the angle of emergence $e = 0$,which implies $r_2 = 0$. Therefore,$A = r_1$. Using Snell's law at the first surface: $n = \frac{\sin i}{\sin r_1}$. Substituting $r_1 = A$,we get $n = \frac{\sin i}{\sin A}$. For a thin prism,the angles $i$ and $A$ are very small,so $\sin i \approx i$ and $\sin A \approx A$. Thus,$n = \frac{i}{A}$,which gives $i = An$.

Class 12 Physics Ray Optics and Optical Instruments Refraction Through Prism

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$A$ ray of light is incident at an angle '$i$' on one face of a thin prism. The ray emerges normally from the other face. If the refractive index of the glass prism is '$n$' and the angle of the prism is '$A$',then the value of '$i$' is:

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A
$An$
B
$An^2$
C
$\frac{A}{n}$
D
$\frac{A}{n^2}$

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Ray Optics and Optical Instruments

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Refraction Through Prism

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$A$ ray of light is incident at an angle '$i$' on one face of a thin prism. The ray emerges normally from the other face. If the refractive index of the glass prism is '$n$' and the angle of the prism is '$A$',then the value of '$i$' is:

Similar Questions

$A$ prism is made up of material of refractive index $\sqrt{3}$. The angle of the prism is $A$. If the angle of minimum deviation is equal to the angle of the prism,then the value of $A$ is: (in $^{\circ}$)

The refractive index of glass for red light is $1.520$ and for blue light is $1.525$. Let $D_1$ and $D_2$ be the angles of deviation for red and blue light,respectively,in a prism of this glass. Then:

The ratio of the angle of minimum deviation produced by a thin prism $(\mu = 3/2)$ in air to that in a liquid of refractive index $9/7$ is:

$A$ light ray is incident at an angle of $60^o$ on a prism of angle $45^o$. When the light ray emerges from the other surface at $90^o$ to the surface,the refractive index of the material of the prism $\mu$ and the angle of deviation $\delta$ are given by:

$A$ small-angled prism is made of a material of refractive index $\frac{3}{2}$. The ratio of the angles of minimum deviation when the prism is placed in air and in water of refractive index $\frac{4}{3}$ is:

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