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(A) The kinetic energy $K$ and linear momentum $p$ of a body of mass $m$ are related by the formula: $K = \frac{p^2}{2m}$.From this,we can express mom

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$2: 1$

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(A) The kinetic energy $K$ and linear momentum $p$ of a body of mass $m$ are related by the formula: $K = \frac{p^2}{2m}$.From this,we can express momentum as: $p = \sqrt{2mK}$.Given that both masses have equal kinetic energy $(K_1 = K_2 = K)$,the ratio of their momenta is:$\frac{p_1}{p_2} = \frac{\sqrt{2m_1K}}{\sqrt{2m_2K}} = \sqrt{\frac{m_1}{m_2}}$.Substituting the given masses $m_1 = 4 \,kg$ and $m_2 = 1 \,kg$:$\frac{p_1}{p_2} = \sqrt{\frac{4}{1}} = \frac{2}{1}$.Thus,the ratio of the magnitude of their linear momenta is $2: 1$.

$A$ $4 \,kg$ mass and a $1 \,kg$ mass are moving with equal kinetic energies. The ratio of the magnitude of their linear momenta is

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