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(D) The electric field $\vec{E}$ is uniform and directed along the positive $Y$-axis.Points $A(0,0)$ and $C(2,0)$ lie on the $X$-axis,which is perpend

Vedclass · Accepted Answer

$V_A = V_C > V_B$

Vedclass · Answer

(D) The electric field $\vec{E}$ is uniform and directed along the positive $Y$-axis.Points $A(0,0)$ and $C(2,0)$ lie on the $X$-axis,which is perpendicular to the direction of the electric field. Therefore,the electric potential at these points is the same,i.e.,$V_A = V_C$.The electric potential decreases in the direction of the electric field. Since point $B(0,2)$ is at a higher $Y$-coordinate than points $A$ and $C$,it is at a lower potential.Thus,$V_A = V_C > V_B$.

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