$A$ battery has an $e.m.f.$ of $4 \ V$ and an internal resistance of $r$. When the battery is connected to an external resistance of $2 \ \Omega$,a current of $1 \ A$ flows through the circuit. If the terminals of the battery are short-circuited (connected directly),what will be the current in $A$ flowing through it?
- A$1$
- B$2$
- C$4$
- DInfinite
Explore More
Similar Questions
Two wires of the same material are connected in parallel to a circuit. If the ratio of their lengths is $4/3$ and the ratio of their radii is $2/3$,then the ratio of the electric current flowing through the wires will be .......
Medium
View SolutionFour resistances $40 \ \Omega, 60 \ \Omega, 90 \ \Omega$,and $110 \ \Omega$ form the arms of a quadrilateral $ABCD$. $A$ battery of emf $40 \ V$ with negligible internal resistance is connected across $AC$. Find the potential difference across $BD$. (in $V$)
In an experiment, a graph was plotted of the potential difference $V$ between the terminals of a cell against the circuit current $i$ by varying the load rheostat. The internal conductance of the cell is given by:
Medium
View SolutionThe current flowing through $R_2$ is:
Consider the circuit shown in the figure. The value of the resistance $X$ for which the thermal power generated in it is independent of small variations of its resistance is
MediumWBJEE 2017
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo