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(B) The terminal voltage $V$ of a battery is given by the equation $V = E - Ir$, where $E$ is the electromotive force, $I$ is the current, and $r$ is

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$y/x$

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(B) The terminal voltage $V$ of a battery is given by the equation $V = E - Ir$, where $E$ is the electromotive force, $I$ is the current, and $r$ is the internal resistance.Comparing this with the equation of a straight line $y = mx + c$, we have $V = -rI + E$.The slope of the $V-I$ graph is $m = -r$. From the given graph, the magnitude of the slope is $|m| = \frac{	ext{rise}}{	ext{run}} = x / v$.Therefore, the internal resistance $r = x / v$.Conductance is the reciprocal of resistance. Thus, internal conductance $G = 1 / r = v / x$.Given the labels in the image, the vertical intercept is $x$ and the horizontal intercept is $v$. The internal conductance is $v/x$.

In an experiment, a graph is plotted between the potential difference across the terminals of a battery and the current in the circuit. The internal conductance of the battery will be:

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