यदि $\alpha \in (0, \pi/2)$ है,तो $\sqrt{x^2 + x} + \frac{\tan^2 \alpha}{\sqrt{x^2 + x}} = \dots$

  • A
    $2 \tan \alpha$
  • B
    $1$
  • C
    $2$
  • D
    $\sec^2 \alpha$

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