For a triangle $ABC$,if $\vec{AB} = 3\hat{i} + 4\hat{k}$ and $\vec{AC} = 5\hat{i} - 2\hat{j} + 4\hat{k}$,then the length of the median drawn from vertex $A$ is:

  • A
    $\sqrt{288}$
  • B
    $\sqrt{18}$
  • C
    $\sqrt{72}$
  • D
    $\sqrt{33}$

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