What is the slope of the tangent drawn from t | vedclass

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(B) The equation of a tangent with slope $m$ to the parabola $y^2 = 4ax$ is $y = mx + \frac{a}{m}$.Here,$4a = 9$,so $a = \frac{9}{4}$.The equation of

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$\frac{1}{4}, \frac{9}{4}$

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(B) The equation of a tangent with slope $m$ to the parabola $y^2 = 4ax$ is $y = mx + \frac{a}{m}$.Here,$4a = 9$,so $a = \frac{9}{4}$.The equation of the tangent is $y = mx + \frac{9}{4m}$.Since the tangent passes through the point $(4, 10)$,we have:$10 = 4m + \frac{9}{4m}$Multiplying by $4m$,we get:$40m = 16m^2 + 9$$16m^2 - 40m + 9 = 0$$(4m - 1)(4m - 9) = 0$Thus,$m = \frac{1}{4}$ or $m = \frac{9}{4}$.

What is the slope of the tangent drawn from the point $(4, 10)$ to the parabola $y^2 = 9x$?

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