$A$ ball of mass $m$ is released from the top of a smooth movable wedge of mass $m$. When the ball collides with the floor,the velocity of the wedge is $v$. Then the maximum height attained by the ball after an elastic collision with the floor is: (Neglect any edge at the lower end of the wedge).

  • A
    $\frac{2v^2}{g}$
  • B
    $\frac{v^2}{4g}$
  • C
    $\frac{4v^2}{g}$
  • D
    $\frac{v^2}{2g}$

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