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(B) The bulk modulus $B$ is defined as $B = -\frac{\Delta P}{\Delta V / V}$,where $\Delta P$ is the change in pressure,$V$ is the initial volume,and $

Vedclass · Accepted Answer

$-43.2\, mm^3$

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(B) The bulk modulus $B$ is defined as $B = -\frac{\Delta P}{\Delta V / V}$,where $\Delta P$ is the change in pressure,$V$ is the initial volume,and $\Delta V$ is the change in volume.Rearranging for $\Delta V$,we get $\Delta V = -\frac{\Delta P \cdot V}{B}$.The initial volume $V = (60\, mm)^3 = 216000\, mm^3 = 2.16 	imes 10^5\, mm^3$.Given $\Delta P = 2.5 	imes 10^7\, Pa$ and $B = 1.25 	imes 10^{11}\, N/m^2$.Substituting the values: $\Delta V = -\frac{2.5 	imes 10^7}{1.25 	imes 10^{11}} 	imes (60\, mm)^3$.$\Delta V = -2 	imes 10^{-4} 	imes 216000\, mm^3 = -43.2\, mm^3$.

$A$ copper solid cube of $60\, mm$ side is subjected to a pressure of $2.5 \times 10^7\, Pa$. If the bulk modulus of copper is $1.25 \times 10^{11}\, N/m^2$,the change in the volume of the cube is:

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