A glass hemisphere of radius 0.04, m and refr | vedclass

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(B) Case $(i)$: When the flat face is in contact with the paper,the light rays from the cross mark travel from the glass to the air. Since the rays ar

Vedclass · Accepted Answer

$(i)$ At the same position of the cross mark; $(ii) \,0.025\, m$ below the flat face

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(B) Case $(i)$: When the flat face is in contact with the paper,the light rays from the cross mark travel from the glass to the air. Since the rays are incident normally on the flat surface,they pass undeviated. Thus,the image is formed at the same position as the cross mark.Case $(ii)$: When the curved face is in contact with the paper,the apparent depth $h'$ is given by the formula $\mu = \frac{	ext{Real depth } (h)}{	ext{Apparent depth } (h')}$.Here,the real depth $h = 0.04\, m$ and the refractive index $\mu = 1.6$.Therefore,$1.6 = \frac{0.04}{h'}$.$h' = \frac{0.04}{1.6} = 0.025\, m$.This image is formed $0.025\, m$ below the flat face.

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