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(D) Height $(h)$ of the cylindrical part $= 8 \, cm$.Radius $(r_{2})$ of the cylindrical part $= \frac{2}{2} = 1 \, cm$.Radius $(r_{1})$ of the spheri

Vedclass · Accepted Answer

$346.51$

Vedclass · Answer

(D) Height $(h)$ of the cylindrical part $= 8 \, cm$.Radius $(r_{2})$ of the cylindrical part $= \frac{2}{2} = 1 \, cm$.Radius $(r_{1})$ of the spherical part $= \frac{8.5}{2} = 4.25 \, cm$.Volume of the vessel $=$ Volume of the sphere $+$ Volume of the cylinder.Volume $= \frac{4}{3} \pi r_{1}^{3} + \pi r_{2}^{2} h$.Volume $= \frac{4}{3} 	imes 3.14 	imes (4.25)^{3} + 3.14 	imes (1)^{2} 	imes 8$.Volume $= \frac{4}{3} 	imes 3.14 	imes 76.765625 + 3.14 	imes 8$.Volume $= 321.392 + 25.12 = 346.512 \, cm^{3}$.Since the calculated volume is $346.512 \, cm^{3}$,the child's measurement of $345 \, cm^{3}$ is incorrect.

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