A tank is in the form of a cylinder with radi | vedclass

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(A) The tank consists of a cylinder and two hemispheres at the ends.Radius of the cylinder $(r)$ = $21\, cm$.Radius of the hemispheres $(r)$ = $21\, c

Vedclass · Accepted Answer

$66.528$

Vedclass · Answer

(A) The tank consists of a cylinder and two hemispheres at the ends.Radius of the cylinder $(r)$ = $21\, cm$.Radius of the hemispheres $(r)$ = $21\, cm$.Total height of the tank = $62\, cm$.Height of the cylindrical part $(h)$ = Total height - $2 	imes$ radius of hemisphere = $62 - 2(21) = 62 - 42 = 20\, cm$.Volume of the tank = Volume of cylinder + $2 	imes$ Volume of hemisphere.Volume = $\pi r^2 h + 2 	imes (2/3) \pi r^3 = \pi r^2 (h + 4/3 r)$.Volume = $(22/7) 	imes (21)^2 	imes (20 + (4/3) 	imes 21) = (22/7) 	imes 441 	imes (20 + 28) = 22 	imes 63 	imes 48 = 66528\, cm^3$.Since $1000\, cm^3 = 1\, liter$, the volume in liters = $66528 / 1000 = 66.528\, liters$.

$A$ tank is in the form of a cylinder with radius $21\, cm$ closed at both the ends by hemispheres. If the total height of the tank is $62\, cm$, how many litres of water can it store? (in $liters$)

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