Calculate the lambda associated with an elect | vedclass

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Question

(A) According to the de Broglie equation,$\lambda = \frac{h}{mv}$.Given: Mass of electron $m = 9.11 	imes 10^{-31} \ kg$,Velocity $v = c = 3 	imes 1

Vedclass · Accepted Answer

$2.43 	imes 10^{-12} \ m$

Vedclass · Answer

(A) According to the de Broglie equation,$\lambda = \frac{h}{mv}$.Given: Mass of electron $m = 9.11 	imes 10^{-31} \ kg$,Velocity $v = c = 3 	imes 10^8 \ m/s$,Planck's constant $h = 6.626 	imes 10^{-34} \ J \cdot s$.Substituting the values: $\lambda = \frac{6.626 	imes 10^{-34}}{9.11 	imes 10^{-31} 	imes 3 	imes 10^8}$.$\lambda = \frac{6.626 	imes 10^{-34}}{27.33 	imes 10^{-23}} \approx 0.2424 	imes 10^{-11} \ m = 2.424 	imes 10^{-12} \ m$.Rounding to the nearest option,the correct value is approximately $2.43 	imes 10^{-12} \ m$.

Calculate the $\lambda$ associated with an electron moving with the velocity of light.

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