Can any term of the A.P. 3, 7, 11, ldots be 1 | vedclass

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(B) The given $A.P.$ is $3, 7, 11, \ldots$ Here,the first term $a = 3$ and the common difference $d = 7 - 3 = 4$. Let the $n^{th}$ term of the $A.P.$

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(B) The given $A.P.$ is $3, 7, 11, \ldots$ Here,the first term $a = 3$ and the common difference $d = 7 - 3 = 4$. Let the $n^{th}$ term of the $A.P.$ be $184$. The formula for the $n^{th}$ term is $a_n = a + (n - 1)d$. Substituting the values,we get: $184 = 3 + (n - 1)4$. $184 - 3 = 4(n - 1)$. $181 = 4(n - 1)$. $n - 1 = 181 / 4 = 45.25$. $n = 45.25 + 1 = 46.25$. Since $n$ must be a positive integer,$184$ cannot be a term of this $A.P.$

Can any term of the $A.P.$ $3, 7, 11, \ldots$ be $184$?

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