Construction of a cumulative frequency table | vedclass

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(A) cumulative frequency table is a statistical tool used to organize data by summing the frequencies of each class interval up to a certain point.Thi

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median

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(A) cumulative frequency table is a statistical tool used to organize data by summing the frequencies of each class interval up to a certain point.This table is specifically required to calculate the median of a grouped frequency distribution.The formula for the median is $Median = l + \left( \frac{\frac{n}{2} - cf}{f} ight) 	imes h$,where $cf$ represents the cumulative frequency of the class preceding the median class.While mean and mode can be calculated using simple frequency tables,the cumulative frequency is essential for the median.

Life time (in hours)	Number of lamps
$1500-2000$	$14$
$2000-2500$	$56$
$2500-3000$	$60$
$3000-3500$	$86$
$3500-4000$	$74$
$4000-4500$	$62$
$4500-5000$	$48$

Class interval	Frequency
$0-100$	$2$
$100-200$	$5$
$200-300$	$x$
$300-400$	$12$
$400-500$	$17$
$500-600$	$20$
$600-700$	$y$
$700-800$	$9$
$800-900$	$7$
$900-1000$	$4$

Construction of a cumulative frequency table is useful in determining the

Similar Questions

To draw the 'less than' type Ogive,........... is represented on the $X$-axis.

In the formula $M = l + \frac{(\frac{n}{2} - cf)}{f} \times h$ for the median,$l = \ldots \ldots \ldots$

In the formula $M = l + \frac{(\frac{n}{2} - cf)}{f} \times h$ for the median,$f = \ldots \ldots \ldots$

The following table gives the distribution of the lifetime of $400$ neon lamps:
Life time (in hours) Number of lamps
$1500-2000$ $14$
$2000-2500$ $56$
$2500-3000$ $60$
$3000-3500$ $86$
$3500-4000$ $74$
$4000-4500$ $62$
$4500-5000$ $48$

Find the median lifetime of a lamp.

The median of the following data is $525$. Find the values of $x$ and $y$,if the total frequency is $100$.
Class interval Frequency
$0-100$ $2$
$100-200$ $5$
$200-300$ $x$
$300-400$ $12$
$400-500$ $17$
$500-600$ $20$
$600-700$ $y$
$700-800$ $9$
$800-900$ $7$
$900-1000$ $4$

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