Five identical capacitor plates,each of area | vedclass

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(C) Let the potential of the positive terminal be $V$ and the negative terminal be $0$. Plates $1, 3, 5$ are connected to the positive terminal (poten

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$\epsilon_0 AV/d, -2\epsilon_0 AV/d$

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(C) Let the potential of the positive terminal be $V$ and the negative terminal be $0$. Plates $1, 3, 5$ are connected to the positive terminal (potential $V$). Plates $2, 4$ are connected to the negative terminal (potential $0$). The potential difference across each adjacent pair of plates is $V$. Charge on plate $1$: It has only one face (inner) facing plate $2$. The charge is $q_1 = C_{eff} V = (\epsilon_0 A/d) V$. Charge on plate $4$: It has two faces (both sides) facing plates $3$ and $5$. Both faces contribute to the charge. Charge on left face of plate $4$ (facing plate $3$) is $-(\epsilon_0 A/d) V$. Charge on right face of plate $4$ (facing plate $5$) is $-(\epsilon_0 A/d) V$. Total charge on plate $4$ is $q_4 = -(\epsilon_0 A/d) V - (\epsilon_0 A/d) V = -2\epsilon_0 AV/d$.

Five identical capacitor plates,each of area $A$,are arranged such that adjacent plates are at a distance $d$ apart. The plates are connected to a source of $emf$ $V$ as shown in the figure. Then the charges on plates $1$ and $4$ are,respectively:

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