For the science fair,a student prepared a mod | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Radius of the cylinder $=$ radius of each cone $= r = 10 \,cm$.Height of the cylinder $H = 40 \,cm$.Slant height of the cone $l = 26 \,cm$.For the

Vedclass · Accepted Answer

$17.6$

Vedclass · Answer

(B) Radius of the cylinder $=$ radius of each cone $= r = 10 \,cm$.Height of the cylinder $H = 40 \,cm$.Slant height of the cone $l = 26 \,cm$.For the cone,$l^2 = r^2 + h^2$,where $h$ is the height of the cone.$h = \sqrt{l^2 - r^2} = \sqrt{26^2 - 10^2} = \sqrt{676 - 100} = \sqrt{576} = 24 \,cm$.Volume of the combined container $=$ Volume of the cylinder $+ 2 	imes$ Volume of the cone.Volume $= \pi r^2 H + 2 	imes (\frac{1}{3} \pi r^2 h) = \pi r^2 (H + \frac{2}{3} h)$.Substituting the values: Volume $= \frac{22}{7} 	imes 10^2 	imes (40 + \frac{2}{3} 	imes 24) = \frac{22}{7} 	imes 100 	imes (40 + 16) = \frac{22}{7} 	imes 100 	imes 56$.Volume $= 22 	imes 100 	imes 8 = 17600 \,cm^3$.Since $1000 \,cm^3 = 1 \,litre$,the volume in litres is $\frac{17600}{1000} = 17.6 \,litres$.Thus,the model can contain $17.6 \,litres$ of water.

For the science fair,a student prepared a model in the shape of a cylinder with radius $10 \,cm$ and height $40 \,cm$,closed at both ends by cones with slant height $26 \,cm$. How many litres of water can it contain?

Similar Questions

$A$ solid piece of iron in the form of a cuboid of dimensions $49 \, cm \times 33 \, cm \times 24 \, cm$ is moulded to form a solid sphere. The radius of the sphere is (in $cm$):

The volume of a cylinder with radius and height both $5 \, cm$ is $\ldots \ldots \ldots \pi \, cm^{3}$.

The volume of a sphere is equal to $\ldots \ldots \ldots . .$

$A$ hemispherical tank full of water is emptied by a pipe at the rate of $3 \frac{4}{7}$ $litres$ per $second.$ How much time will it take to empty half the tank,if it is $3 \,m$ in $diameter?$ (in $minutes$) (Take $\pi=\frac{22}{7}$)

If the radius of a sphere is doubled,its volume becomes $\ldots \ldots \ldots \ldots$ times the original volume.

Vedclass Test Series

Exam Paper Generator

Online Exam Module