Graphically,the pair of equations 6x - 3y + 1 | vedclass

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(C) The given equations are:$6x - 3y + 10 = 0$ ... $(1)$$2x - y + 9 = 0$ ... $(2)$Comparing these with the general form $a_1x + b_1y + c_1 = 0$ and $a

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parallel.

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(C) The given equations are:$6x - 3y + 10 = 0$ ... $(1)$$2x - y + 9 = 0$ ... $(2)$Comparing these with the general form $a_1x + b_1y + c_1 = 0$ and $a_2x + b_2y + c_2 = 0$,we have:$a_1 = 6, b_1 = -3, c_1 = 10$$a_2 = 2, b_2 = -1, c_2 = 9$Now,calculate the ratios:$\frac{a_1}{a_2} = \frac{6}{2} = 3$$\frac{b_1}{b_2} = \frac{-3}{-1} = 3$$\frac{c_1}{c_2} = \frac{10}{9}$Since $\frac{a_1}{a_2} = \frac{b_1}{b_2} 
eq \frac{c_1}{c_2}$,the lines are parallel to each other and do not intersect.

Graphically,the pair of equations $6x - 3y + 10 = 0$ and $2x - y + 9 = 0$ represents two lines which are:

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