Identify an aromatic,mixed,3^{circ} amine amo | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) An aromatic amine is one where the nitrogen atom is directly attached to an aromatic ring.$A$ mixed amine (or unsymmetrical amine) has different a

Vedclass · Accepted Answer

$C_6H_5N(CH_3)_2$

Vedclass · Answer

(D) An aromatic amine is one where the nitrogen atom is directly attached to an aromatic ring.$A$ mixed amine (or unsymmetrical amine) has different alkyl or aryl groups attached to the nitrogen atom.$A$ $3^{\circ}$ (tertiary) amine has three groups (alkyl or aryl) attached to the nitrogen atom.Let us analyze the options:$A$: $C_6H_5NHC_2H_5$ is an aromatic,mixed,$2^{\circ}$ amine.$B$: $(C_2H_5)_3N$ is an aliphatic,simple,$3^{\circ}$ amine.$C$: $(CH_3)_3N$ is an aliphatic,simple,$3^{\circ}$ amine.$D$: $C_6H_5N(CH_3)_2$ ($N$,$N$-dimethylaniline) has a phenyl group and two methyl groups attached to the nitrogen. It is aromatic,mixed,and a $3^{\circ}$ amine.Therefore,the correct option is $D$.

Identify an aromatic,mixed,$3^{\circ}$ amine among the following compounds.

Similar Questions

$CH_3-CH_2-NH_2 \xrightarrow{CHCl_3, KOH} \text{Product}$

The major product $(R)$ of the following reaction is:
$C_6H_5NH_2$ $\xrightarrow[{0 \, ^\circ C}]{{HNO_2}} P$ $\xrightarrow{{HBF_4}} Q$ $\xrightarrow[{Cu, \, \Delta }]{{NaNO_2}} R$

The reaction of chloroform with alcoholic $KOH$ and $p-$toluidine forms:

Decarboxylation of all six possible isomers of diaminobenzoic acids $C_6H_3(NH_2)_2COOH$ yields three products $A, B$ and $C$. Three acids give product $A$,two acids give product $B$ and one acid gives product $C$. The melting point of product $C$ is .....$^{\circ} C$.

What is obtained by the ammonolysis of alkyl halides?

Vedclass Test Series

Exam Paper Generator

Online Exam Module