If $x+\frac{1}{x}=2,$ then the value of $x^{2}+\frac{1}{x^{2}}$ will be
- A$1$
- B$2$
- C$3$
- D$4$
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Similar Questions
Solve the given two equations and select the correct answer from the given options.
$I.$ $3216 x^{2} + 3859 x + 481 = 0$
$II.$ $8132 y^{2} - 4839 y + 978 = 0$
$I.$ $3216 x^{2} + 3859 x + 481 = 0$
$II.$ $8132 y^{2} - 4839 y + 978 = 0$
Medium
View SolutionSolve the given two equations and select the correct answer from the given options.
$I. x^{2}-19x+84=0$
$II. y^{2}-25y+156=0$
$I. x^{2}-19x+84=0$
$II. y^{2}-25y+156=0$
Difficult
View SolutionSolve the given two equations and select the correct option.
$I.$ $x^{2} + 42 = 13x$
$II.$ $y = \sqrt[4]{1296}$
$I.$ $x^{2} + 42 = 13x$
$II.$ $y = \sqrt[4]{1296}$
Medium
View SolutionIf $l, m, n$ are real and $l \ne m$,then the roots of the equation $(l - m)x^2 - 5(l + m)x - 2(l - m) = 0$ are
Easy
View SolutionSolve the given two equations and select the correct answer from the given options.
$I.$ $16 x^{2}+20 x+6=0$
$II.$ $10 y^{2}+38 y+24=0$
$I.$ $16 x^{2}+20 x+6=0$
$II.$ $10 y^{2}+38 y+24=0$
Difficult
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