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(C) For equation $I$: $3216 x^{2} + 3859 x + 481 = 0$.Since all coefficients are positive,the roots of this quadratic equation must be negative.For eq

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if $x < y$

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(C) For equation $I$: $3216 x^{2} + 3859 x + 481 = 0$.Since all coefficients are positive,the roots of this quadratic equation must be negative.For equation $II$: $8132 y^{2} - 4839 y + 978 = 0$.Here,the signs of the coefficients are $(+, -, +)$. According to the sign rule for quadratic equations $ax^{2} + bx + c = 0$,if the signs are $(+, -, +)$,both roots are positive.Since all values of $x$ are negative and all values of $y$ are positive,it follows that $y > x$ or $x < y$.

Solve the given two equations and select the correct answer from the given options.
$I.$ $3216 x^{2} + 3859 x + 481 = 0$
$II.$ $8132 y^{2} - 4839 y + 978 = 0$

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Solve the given two equations and select the correct answer from the given options.$I.$ $3216 x^{2} + 3859 x + 481 = 0$$II.$ $8132 y^{2} - 4839 y + 978 = 0$