If x^{2}+kx+6=(x+2)(x+3) for all x,then the v | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given the equation: $x^{2}+kx+6=(x+2)(x+3)$.First,expand the right side of the equation:$(x+2)(x+3) = x(x+3) + 2(x+3)$$= x^{2} + 3x + 2x + 6$$= x^

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(A) Given the equation: $x^{2}+kx+6=(x+2)(x+3)$.First,expand the right side of the equation:$(x+2)(x+3) = x(x+3) + 2(x+3)$$= x^{2} + 3x + 2x + 6$$= x^{2} + 5x + 6$.Now,compare this with the left side of the equation: $x^{2}+kx+6 = x^{2}+5x+6$.By comparing the coefficients of $x$ on both sides,we get $k = 5$.

If $x^{2}+kx+6=(x+2)(x+3)$ for all $x$,then the value of $k$ is

Similar Questions

Find the value of $m$ so that $2x - 1$ is a factor of $8x^4 + 4x^3 - 16x^2 + 10x + m$.

Factorise the following quadratic polynomial by splitting the middle term:
$15x^2 + 7x - 2$

Find the quotient and the remainder when $x^{3}+x^{2}-10x+8$ is divided by $x-2$.

The factorisation of $4 x^{2}+8 x+3$ is

Factorise $x^{3}-23 x^{2}+142 x-120$

Vedclass Test Series

Exam Paper Generator

Online Exam Module