If p(x) = x^{2} - 4x + 3,then find the value | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given the polynomial $p(x) = x^{2} - 4x + 3$.First,calculate $p(2)$:$p(2) = (2)^{2} - 4(2) + 3 = 4 - 8 + 3 = -1$.Next,calculate $p(-1)$:$p(-1) = (

Vedclass · Accepted Answer

$-31$

Vedclass · Answer

(B) Given the polynomial $p(x) = x^{2} - 4x + 3$.First,calculate $p(2)$:$p(2) = (2)^{2} - 4(2) + 3 = 4 - 8 + 3 = -1$.Next,calculate $p(-1)$:$p(-1) = (-1)^{2} - 4(-1) + 3 = 1 + 4 + 3 = 8$.Then,calculate $p(1/2)$:$p(1/2) = (1/2)^{2} - 4(1/2) + 3 = 1/4 - 2 + 3 = 1/4 + 1 = 5/4$.Finally,substitute these values into the expression $p(2) - p(-1) + p(1/2)$:$-1 - 8 + 5/4 = -9 + 5/4 = (-36 + 5) / 4 = -31/4$.

If $p(x) = x^{2} - 4x + 3$,then find the value of $p(2) - p(-1) + p(1/2)$. (in $/4$)

Similar Questions

Write the coefficient of $x^{2}$ in the following polynomial:
$\sqrt{5}x^{2} - 7x + 13$

Find the value of the following polynomial at the indicated value of the variable:
$p(t) = 5t^{2} - 11t + 7$ at $t = a$

Write the coefficient of $x^{2}$ in the following polynomial: $x^{3} + 27$.

Is the following expression a polynomial? Justify your answer:
$\frac{1}{5 x^{-2}}+5 x+7$

Find $p(0)$,$p(1)$,and $p(2)$ for the following polynomial: $p(x) = x^{3}$

Vedclass Test Series

Exam Paper Generator

Online Exam Module