If $\alpha, \beta$ and $\gamma$ are the roots of the equation $2x^3 - 3x^2 + 6x + 1 = 0$,then $\alpha^2 + \beta^2 + \gamma^2$ is equal to

  • A
    $-\frac{15}{4}$
  • B
    $\frac{15}{4}$
  • C
    $\frac{9}{4}$
  • D
    $4$

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