यदि bar{a}, bar{b}, bar{c} असमतलीय सदिश हैं औ | vedclass

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(C) दिया गया है कि $\bar{p}=\frac{\bar{b} 	imes \bar{c}}{[\bar{a} \bar{b} \bar{c}]}, \bar{q}=\frac{\bar{c} 	imes \bar{a}}{[\bar{a} \bar{b} \bar{c}]}

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(C) दिया गया है कि $\bar{p}=\frac{\bar{b} 	imes \bar{c}}{[\bar{a} \bar{b} \bar{c}]}, \bar{q}=\frac{\bar{c} 	imes \bar{a}}{[\bar{a} \bar{b} \bar{c}]}, \bar{r}=\frac{\bar{a} 	imes \bar{b}}{[\bar{a} \bar{b} \bar{c}]}$ है।हम जानते हैं कि अदिश त्रिक गुणनफल $[\bar{a} \bar{b} \bar{c}] = \bar{a} \cdot (\bar{b} 	imes \bar{c})$ होता है।अब,प्रत्येक पद की गणना करें:$\bar{a} \cdot \bar{p} = \bar{a} \cdot \left( \frac{\bar{b} 	imes \bar{c}}{[\bar{a} \bar{b} \bar{c}]} ight) = \frac{\bar{a} \cdot (\bar{b} 	imes \bar{c})}{[\bar{a} \bar{b} \bar{c}]} = \frac{[\bar{a} \bar{b} \bar{c}]}{[\bar{a} \bar{b} \bar{c}]} = 1$.इसी प्रकार,$\bar{b} \cdot \bar{q} = \bar{b} \cdot \left( \frac{\bar{c} 	imes \bar{a}}{[\bar{a} \bar{b} \bar{c}]} ight) = \frac{\bar{b} \cdot (\bar{c} 	imes \bar{a})}{[\bar{a} \bar{b} \bar{c}]} = \frac{[\bar{b} \bar{c} \bar{a}]}{[\bar{a} \bar{b} \bar{c}]} = \frac{[\bar{a} \bar{b} \bar{c}]}{[\bar{a} \bar{b} \bar{c}]} = 1$.और $\bar{c} \cdot \bar{r} = \bar{c} \cdot \left( \frac{\bar{a} 	imes \bar{b}}{[\bar{a} \bar{b} \bar{c}]} ight) = \frac{\bar{c} \cdot (\bar{a} 	imes \bar{b})}{[\bar{a} \bar{b} \bar{c}]} = \frac{[\bar{c} \bar{a} \bar{b}]}{[\bar{a} \bar{b} \bar{c}]} = \frac{[\bar{a} \bar{b} \bar{c}]}{[\bar{a} \bar{b} \bar{c}]} = 1$.अतः,$\bar{a} \cdot \bar{p} + \bar{b} \cdot \bar{q} + \bar{c} \cdot \bar{r} = 1 + 1 + 1 = 3$.

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