If A = begin{bmatrix} 0 & 0 & 1 0 & 1 & 0 1 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given the matrix $A = \begin{bmatrix} 0 & 0 & 1 \ 0 & 1 & 0 \ 1 & 0 & 0 \end{bmatrix}$.First,we calculate $A^2 = A 	imes A$:$A^2 = \begin{bmatr

Vedclass · Accepted Answer

$A$

Vedclass · Answer

(D) Given the matrix $A = \begin{bmatrix} 0 & 0 & 1 \ 0 & 1 & 0 \ 1 & 0 & 0 \end{bmatrix}$.First,we calculate $A^2 = A 	imes A$:$A^2 = \begin{bmatrix} 0 & 0 & 1 \ 0 & 1 & 0 \ 1 & 0 & 0 \end{bmatrix} \begin{bmatrix} 0 & 0 & 1 \ 0 & 1 & 0 \ 1 & 0 & 0 \end{bmatrix} = \begin{bmatrix} 1 & 0 & 0 \ 0 & 1 & 0 \ 0 & 0 & 1 \end{bmatrix} = I$.Since $A^2 = I$,we can multiply both sides by $A^{-1}$:$A^2 \cdot A^{-1} = I \cdot A^{-1}$$A \cdot (A \cdot A^{-1}) = A^{-1}$$A \cdot I = A^{-1}$Therefore,$A^{-1} = A$.

If $A = \begin{bmatrix} 0 & 0 & 1 \\ 0 & 1 & 0 \\ 1 & 0 & 0 \end{bmatrix}$,then $A^{-1} = $

Similar Questions

If $A = \begin{bmatrix} \cos x & \sin x \\ -\sin x & \cos x \end{bmatrix}$,then $A \cdot (adj(A)) = $

Let $A$ be a $3 \times 3$ matrix and $B$ be its adjoint matrix. If $|B|=64,$ then $|A|$ is equal to

If a matrix $A$ is such that $3A^3 + 2A^2 + 5A + I = 0$,then its inverse is

If $A = \begin{bmatrix} x & 1 \\ 1 & 0 \end{bmatrix}$ and $A = A^{-1}$,then $x = \dots$

Matrix $A = \begin{bmatrix} x & 3 & 2 \\ 1 & y & 4 \\ 2 & 2 & z \end{bmatrix}$. If $xyz = 60$ and $8x + 4y + 3z = 20$,then $A (adj A)$ is equal to:

Vedclass Test Series

Exam Paper Generator

Online Exam Module