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(A) For the equation $ax^2+6xy-2y^2=0$ to represent a pair of perpendicular lines,the sum of the coefficients of $x^2$ and $y^2$ must be zero.$a + (-2

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$3a$

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(A) For the equation $ax^2+6xy-2y^2=0$ to represent a pair of perpendicular lines,the sum of the coefficients of $x^2$ and $y^2$ must be zero.$a + (-2) = 0 \Rightarrow a = 2$.For the equation $9x^2+2hxy+4y^2=0$ to represent a pair of coincident lines,the condition $h^2 - ab = 0$ must be satisfied,where the equation is of the form $Ax^2 + 2Hxy + By^2 = 0$.Here,$A=9$,$B=4$,and the coefficient of $xy$ is $2h$,so the condition is $h^2 - AB = 0$.$h^2 - (9)(4) = 0 \Rightarrow h^2 = 36$.Since $h > 0$,we have $h = 6$.Given $a = 2$,we can express $h$ in terms of $a$ as $h = 3a$ (since $3 	imes 2 = 6$).

If $ax^2+6xy-2y^2=0$ represents a pair of perpendicular lines and $9x^2+2hxy+4y^2=0$ $(h>0)$ represents a pair of coincident lines,then $h=$

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