જો $y = \sqrt{\sin \sqrt{x}}$ હોય,તો $\frac{dy}{dx} = $

  • A
    $\frac{1}{2\sqrt{\cos \sqrt{x}}}$
  • B
    $\frac{\sqrt{\cos \sqrt{x}}}{2x}$
  • C
    $\frac{\cos \sqrt{x}}{4\sqrt{x} \sqrt{\sin \sqrt{x}}}$
  • D
    $\frac{1}{2\sqrt{\sin x}}$

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